**NCERT Solutions for Class 6 Maths Chapter 7** Decimals is offered to help Class 6 students get introduced to the topic of Decimals and practice the concepts thoroughly.

These **NCERT Solutions for Class 6 Maths Chapter 8** were created by Study Circle subject-matter experts with the intention of offering every approach to solve questions as per the CBSE syllabus. Students are able to practice answering the questions of the chapter and get their solutions.

Students can compare their prepared answers with the** NCERT Solutions for Class 6 Maths Chapter 8** and know where they went wrong or what steps they can take to improve.

** NCERT Solutions for Class 6 Maths Chapter 8 **

**Exercise 8.1 **

**Question 1. Which is greater?**

**(a) 0.3 or 0.4**

**(b) 0.07 or 0.02**

**(c) 3 or 0.8**

**(d) 0.5 or 0.05**

**(e) 1.23 or 1.20**

**(f) 0.099 or 0.19**

**(g) 1.5 or 1.50**

**(h) 1.431 or 1.490**

**(i) 3.3 or 3.300**

**(j) 5.64 or 5.603**

**Solutions:**

**(a) **0.3 or 0.4

The whole parts for both numbers are the same. We know that the tenth part of 0.4 is greater than that of 0.3.

∴ 0.4 > 0.3.

**(b)** 0.07 or 0.02

Both the numbers have the same parts up to the tenth place, but the hundredth part of 0.07 is greater than that of 0.02.

∴ 0.07 > 0.02.

**(c)** 3 or 0.8

The whole part of 3 is greater than that of 0.8

∴ 3 > 0.8

**(d)** 0.5 or 0.05

The whole parts for both numbers are the same. Here, the tenth part of 0.5 is greater than that of 0.05.

∴ 0.5 > 0.05.

**(e)** 1.23 or 1.20

Here, both the numbers have the same parts up to the tenth place. The hundredth part of 1.23 is greater than that of 1.20.

∴ 1.23 > 1.20.

**(f)** 0.099 or 0.19

The whole parts for both numbers are the same. Here, the tenth part of 0.19 is greater than that of 0.099.

∴ 0.099 < 0.19.

**(g)** 1.5 or 1.50

We may find that both numbers have the same parts up to the tenth place. Here 1.5 have no digit at the hundredth place. It represents that this digit is 0, which is equal to the digit at the hundredth place of 1.50.

∴ Both these numbers are equal.

**(h)** 1.431 or 1.490

Here, both the numbers have the same parts up to the tenth place, but the hundredth part of 1.490 is greater than that of 1.431.

∴ 1.431 < 1.490.

**(i)** 3.3 or 3.300

Here, both numbers have the same parts up to the tenth place. There are no digits at the hundredth and thousandth place of 3.3. It represents that these numbers are 0, which is equal to the digits at the hundredth and thousandth place of 3.300.

∴ Both these numbers are equal.

**(j)** 5.64 or 5.603

Here, both numbers have the same parts up to the tenth place, but the hundredth part of 5.64 is greater than that of 5.603

∴ 5.64 > 5.603.

**Question 2. Make five more examples and find the greater number from them.**

**Solutions:**

**Five more examples are given below:**

**(a) **32.55 or 32.5

The whole parts for both numbers are the same. The tenth part is also equal, but the hundredth part of 32.55 is greater than that of 32.5.

Hence, 32.55 > 32.5.

**(b)** 1 or 0.99

The whole part of 1 is greater than that of 0.99.

∴ 1 > 0.99.

**(c)** 1.09 or 1.093

Here, both numbers have the same parts up to the hundredth. But the thousandth part of 1.093 is greater than that of 1.09,

∴ 1.093 > 1.09,

**(d)** 2 or 1.99

The whole part of 2 is greater than that of 1.99,

∴ 2 > 1.99,

**(e)** 2.08 or 2.085

Here, both numbers have the same parts up to the hundredth. But the thousandth part of 2.085 is greater than that of 2.08,

∴ 2.085 > 2.08,

**NCERT Solutions for Class 6 Maths Chapter 8 **

**Exercise 8.2**

**Question 1. Express as rupees using decimals.**

**(a) 5 paise**

**(b) 75 paise**

**(c) 20 paise**

**(d) 50 rupees 90 paise**

**(e) 725 paise**

**Solutions:**

We know that there are 100 paise in 1 rupee.

(a) 5 paise = 5 / 100 rupees

= Rupess 0.05

(b) 75 paise = 75 / 100 rupees

= Rupees 0.75

(c) 20 paise = 20 / 100 rupees

= Rupees 0.20

(d) 50 rupees 90 paise = [(50 + 90 / 100)] rupees

= Rupees 50.90

(e) 725 paise = 725 / 100 rupees

= Rupees 7.25

**Question 2. Express as metres using decimals.**

**(a) 15 cm**

**(b) 6 cm**

**(c) 2 m 45 cm**

**(d) 9 m 7 cm**

**(e) 419 cm**

**Solutions:**

We know that there are 100 cm in 1 metre

**(a)** 15 cm = 15 / 100 m

= 0.15 m

**(b)** 6 cm = 6 / 100 m

= 0.06 m

**(c)** 2 m 45 cm = [(2 + 45 / 100)] m

= 2.45 m

**(d)** 9 m 7 cm = [(9 + 7 / 100)] m

= 9.07 m

**(e)** 419 cm = 419 / 100 m

= 4.19 m

**Question 3. Express as cm using decimals**

**(a) 5 mm**

**(b) 60 mm**

**(c) 164 mm**

**(d) 9 cm 8 mm**

**(e) 93 mm**

**Solutions:**

We know that there are 10 mm in 1 cm.

**(a)** 5 mm = 5 / 10 cm

= 0.5 cm

**(b)** 60 mm = 60 / 10 cm

= 6.0 cm

**(c)** 164 mm = 164 / 10 cm

= 16.4 cm

**(d)** 9 cm 8 mm = [(9 + 8 / 10)] cm

= 9.8 cm

**(e)** 93 mm = 93 / 10 cm

= 9.3 cm

**Question 4. Express as km using decimals.**

**(a) 8 m**

**(b) 88 m**

**(c) 8888 m**

**(d) 70 km 5 m**

**Solutions:**

We know that there are 1000 metres in 1 km.

**(a)** 8 m = 8 / 1000 km

= 0.008 km

**(b)** 88 m = 88 / 1000 km

= 0.088 km

**(c)** 8888 m = 8888 / 1000 km

= 8.888 km

**(d)** 70 km 5 m = [(70 + 5 / 1000)] km

= 70.005 km

**Question 5. Express as kg using decimals.**

**(a) 2 g**

**(b) 100 g**

**(c) 3750 g**

**(d) 5 kg 8 g**

**(e) 26 kg 50 g**

**Solutions:**

We know that there are 1000 grams in 1 kg.

**(a)** 2 g = 2 / 1000 kg

= 0.002 kg

**(b)** 100 g = 100 / 1000 kg

= 0.1 kg

**(c)** 3750 g = 3750 / 1000 kg

= 3.750 kg

**(d)** 5 kg 8 g = [(5 + 8 / 1000)] kg

= 5.008 kg

**(e)** 26 kg 50 g = [(26 + 50 / 1000)] kg

= 26.050 kg

**NCERT Solutions for Class 6 Maths Chapter 8 **

**Exercise 8.3**

**Question 1. Find the sum in each of the following:**

**(a) 0.007 + 8.5 + 30.08**

**(b) 15 + 0.632 + 13.8**

**(c) 27.076 + 0.55 + 0.004**

**(d) 25.65 + 9.005 + 3.7**

**(e) 0.75 + 10.425 + 2**

**(f) 280.69 + 25.2 + 38**

**Solutions:**

**(a) **Sum of 0.007 + 8.5 + 30.08

**(b)** Sum of 15 + 0.632 + 13.8

(c) Sum of 27.076 + 0.55 + 0.004

(d) Sum of 25.65 + 9.005 + 3.7

(e) Sum of 0.75 + 10.425 + 2

(f) Sum of 280.69 + 25.2 + 38

**Question 2. Rashid spent ₹ 35.75 for the Maths book and ₹ 32.60 for the Science book. Find the total amount spent by Rashid.**

**Solutions:–**

**Question 3. Radhika’s mother gave her ₹ 10.50, and her father gave her ₹ 15.80. Find the total amount given to Radhika by the parents.**

**Solutions:**

The amount given by Radhika’s mother = ₹ 10.50

The amount given by Radhika’s father = ₹ 15.80

The total amount given by her parents is = 10.50

+ 15.80

26.30

∴ The total amount of money given by Radhika’s parents is ₹ 26.30.

**Question 4. Nasreen bought 3 m 20 cm cloth for her shirt and 2 m 5 cm cloth for her trouser. Find the total length of cloth bought by her.**

**Solutions:**

Cloth of shirt = 3 m 20 cm

Cloth of trouser = 2 m 5 cm

The total length of the cloth is

3.20

+ 2.05

5.25

∴ The total length of cloth bought by Nasreen is 5.25 m.

**Question 5. Naresh walked 2 km 35 m in the morning and 1 km 7 m in the evening. How much distance did he walk in all?**

**Solutions:**

Distance walked by Naresh in the morning = 2 km 35 m

= [(2 + 35 /1000)] km

= 2.035 km

Distance walked by him in the evening = 1 km 7 m

= [(1 + 7 / 1000)] km

= 1.007 km

The total distance walked by Naresh is

2.035

+1.007

3.042

∴ The total distance walked by Naresh is 3.042 km.

**Question 6. Sunita travelled 15 km 268 m by bus, 7 km 7 m by car and 500 m on foot in order to reach her school. How far is her school from her residence?**

**Solutions:**

Distance travelled by bus = 15 km 268 m

= [(15 + 268 / 1000)] km

= 15.268 km

Distance travelled by car = 7 km 7 m

= [(7 + 7 / 1000)] km

= 7.007 km

Distance walked by Sunita = 500 m

= 500 / 1000

= 0.500 km

The total distance of the school from her residence is

15.268

+ 7.007

0.500

22.775

∴ The total distance of the school from her residence is 22.775 km.

**question 7. Ravi purchased 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850 g flour. Find the total weight of his purchases.**

**Solutions:**

Weight of rice = 5 kg 400 g

= [(5 + 400 / 1000)] kg

= 5.400 kg

Weight of sugar = 2 kg 20 g

= [(2 + 20 / 1000)] kg

= 2.020 kg

Weight of flour = 10 kg 850 g

= [(10 + 850 / 1000)] kg

= 10.850 kg

The total weight of his purchases is

5.400

+2.020

10.850

18.270

** NCERT Solutions for Class 6 Maths Chapter 8 **

**Exercise 8.4**

**Question 1. Subtract:**

**(a) ₹ 18.25 from ₹ 20.75**

**(b) 202.54 m from 250 m**

**(c) ₹ 5.36 from ₹ 8.40**

**(d) 2.051 km from 5.206 km**

**(e) 0.314 kg from 2.107 kg**

**Solutions:–**

**(a) **₹ 20.75 – ₹ 18.75

20.75

– 18.25

2.50

₹ 2.50

**(b)** 250 m – 202.54 m

250.00

– 202.54

___________

47.46

____________

47.46 m

**(c)** ₹ 8.40 – ₹ 5.36

8.40

– 5.36

_________

3.04

_________

₹ 3.04

**(d)** 5.206 km – 2.051 km

5.206

– 2.051

__________

3.155

__________

3.155 km

**(e)** 2.107 kg – 0.314 kg

2.107

– 0.314

_________

1.793

__________

1.793 kg

**Question 2. Find the value of the following:**

**(a) 9.756 – 6.28**

**(b) 21.05 – 15.27**

**(c) 18.5 – 6.79**

**(d) 11.6 – 9.847**

**Solutions:**

**(a) **9.756

– 6.280

_________

3.476

_________

(b) 21.05

– 15.27

___________

5.78

____________

(c) 18.50

– 6.79

___________

11.71

___________

(d) 11.600

– 9.847

____________

1.753

____________

**Question 3. Raju bought a book for ₹ 35.65. He gave ₹ 50 to the shopkeeper. How much money did he get back from the shopkeeper?**

**Solutions:**

Money given to shopkeeper = ₹ 50.00

Price of the book = ₹ 35.65

The money Raju will get back from the shopkeeper will be the difference between these two.

∴ The money left with Raju is

50.00

+ 35.65

14.35

Hence, the money left with Raju is ₹ 14.35.

**Question 4. Rani had ₹ 18.50. She bought one ice cream for ₹ 11.75. How much money does she have now?**

**Solutions:**

Money with Rani = ₹ 18.50

Price of an ice cream = ₹ 11.75

Now, the money left with Rani will be the difference between these two.

Hence, the money left with her is

18.50

– 11.75

6.75

∴ The money left with Rani is ₹ 6.75.

**Question 5. Tina had 20 m 5 cm long cloth. She cuts 4 m 50 cm length of cloth from this for making a curtain. How much cloth is left with her?**

**Solutions:**

Length of cloth = 20 m 5 cm

= 20.05 m

Length of cloth to make a curtain = 4 m 50 cm

= 4.50 m

The length of cloth left with Tina will be the difference between these two.

Thus, the length of cloth left with her is

20.05

– 4.50

________

15.55

________

∴ The length of the remaining cloth left with Tina is 15.55 m.

**Question 6. Namita travels 20 km 50 m every day. Out of this, she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto?**

**Solutions:**

Total distance travelled by Namita = 20 km 50 m

= 20.050 km

Distance travelled by bus = 10 km 200 m

= 10.200 km

Distance travelled by auto = Total distance travelled – Distance travelled by bus

∴ Distance to be travelled by auto is

20.050

– 10.200

________

9.850

________

∴ Namita travelled 9.850 km by auto.

**Question 7. Aakash bought vegetables weighing 10 kg. Out of this, 3 kg 500 g is onions, 2 kg 75 g is tomatoes, and the rest is potatoes. What is the weight of the potatoes?**

**Solutions:**

Total weight of vegetables Aakash bought = 10.000 kg

Weight of onions = 3 kg 500 g

= 3.500 kg

Weight of tomatoes = 2 kg 75 g

= 2.075 kg

Weight of potatoes = Total weight of vegetables bought – (weight of onions + weight of tomatoes)

= 10.000 – (3.500 + 2.075)

3.500

+ 2.075

________

5.575

________

10.000

– 5.575

_________

4.425

_________

∴ 4.425 kg is the weight of the potatoes.